BMS-P5 free base

Catalog No.: A46269
PAD4 Inhibitor
BMS-P5 free base is a selective inhibitor of peptidylarginine deiminase 4 (PAD4), demonstrating an IC50 of 98 nM. This compound exhibits specificity for PAD4 over PAD1, PAD2, and PAD3. BMS-P5 free base effectively inhibits multiple myeloma (MM)-induced neutrophil extracellular trap (NET) formation and has been shown to delay the progression of MM in syngeneic mouse models, making it a valuable tool for research in cancer and inflammation.
Grouped product items
Size Price Stock Qty
1mg
$25.00
In stock
5mg
$65.00
In stock
10mg
$120.00
In stock
25mg
$250.00
In stock
50mg
$435.00
In stock
100mg
$605.00
In stock
Bulk Size
Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
Science VOLUME 369, ISSUE 6510 (2020)
Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionBMS-P5 free base is a selective inhibitor of peptidylarginine deiminase 4 (PAD4), demonstrating an IC50 of 98 nM. This compound exhibits specificity for PAD4 over PAD1, PAD2, and PAD3. BMS-P5 free base effectively inhibits multiple myeloma (MM)-induced neutrophil extracellular trap (NET) formation and has been shown to delay the progression of MM in syngeneic mouse models, making it a valuable tool for research in cancer and inflammation.
Product Information
Catalog NumA46269
FormulaC27H32N6O2
Molecular Weight472.58
CAS Number1550371-22-6
SMILESO=C(N1[C@@H](C)CC[C@@H](N)C1)C2=CC(OC)=C3C(N=C(C4=CC5=CC=CN=C5N4CC6CC6)N3C)=C2
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