TR-14035
Catalog No.: A17118
Integrin Antagonist
TR-14035 is a dual antagonist of α4β7 and α4β1 integrins.
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| Description | TR-14035 is a dual antagonist of α4β7 and α4β1 integrins. | |||||
|---|---|---|---|---|---|---|
| Targets |
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| Cell Research |
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| Catalog Num | A17118 |
|---|---|
| Formula | C24H21Cl2NO5 |
| Molecular Weight | 474.33 |
| CAS Number | 232271-19-1 |
| SMILES | O=C(O)[C@H](CC1=CC=C(C2=C(OC)C=CC=C2OC)C=C1)NC(C3=C(Cl)C=CC=C3Cl)=O |
| Synonyms | TR 14035, TR14035 |
| Storage | Store lyophilized at -20ºC, keep desiccated. |
| In vitro | DMSO | 84 mg/mL (177.09 mM) | |
| Water | Insoluble | ||
| Ethanol | 18 mg/mL (37.94 mM) | ||
| * <1 mg/ml means slightly soluble or insoluble. * Please note that Adooq tests the solubility of all compounds in-house, and the actual solubility may differ slightly from published values. This is normal and is due to slight batch-to-batch variations. | |||
| Concentration / Solvent Volume / Mass | 1 mg | 5 mg | 10 mg |
|---|---|---|---|
| 0.1 mM | 21.08 mL | 105.41 mL | 210.82 mL |
| 0.5 mM | 4.22 mL | 21.08 mL | 42.16 mL |
| 1 mM | 2.11 mL | 10.54 mL | 21.08 mL |
| 5 mM | 0.42 mL | 2.11 mL | 4.22 mL |
This calculator helps you calculate mass of compound based on solution concentration, volume and molecular weight in a specific solution using the formula:
Mass (mg) = Concentration (mM) × Volume (mL) × Molecular Weight (g/mol)
Please check COA/MSDS for correct molecular weight.
Calculate the dilution required to prepare a stock solution.This equation is commonly abbreviated as: C1V1 = C2V2