16-Phenoxy tetranor prostaglandin F2α methyl ester

Catalog No.: A63392
Prostaglandin F2α Analogue
16-Phenoxy tetranor Prostaglandin F2α methyl ester is a metabolically stable analogue of Prostaglandin F2α, designed to bind selectively to the FP receptor. This compound functions as a prodrug that can be hydrolyzed to release its bioactive free acid form, enabling its use in various biological assays. Its properties make it suitable for research applications focused on reproductive physiology and other areas involving prostaglandin signaling.
Grouped product items
Size Price Stock Qty
500µg
$160.00
In stock
1mg
$300.00
In stock
5mg
$1,270.00
In stock
Bulk Size
Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
Science VOLUME 369, ISSUE 6510 (2020)
Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
Description16-Phenoxy tetranor Prostaglandin F2α methyl ester is a metabolically stable analogue of Prostaglandin F2α, designed to bind selectively to the FP receptor. This compound functions as a prodrug that can be hydrolyzed to release its bioactive free acid form, enabling its use in various biological assays. Its properties make it suitable for research applications focused on reproductive physiology and other areas involving prostaglandin signaling.
Product Information
Catalog NumA63392
FormulaC23H32O6
Molecular Weight404.50
CAS Number51638-90-5
SMILESO[C@@H]1[C@@H]([C@H]([C@@H](C1)O)/C=C/[C@H](COC2=CC=CC=C2)O)C/C=C\CCCC(OC)=O
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