Cloxacillin sodium

Catalog No.: A46395
Antibiotic Agent
Cloxacillin sodium is a β-lactam antibiotic and a potent β-lactamase inhibitor with an IC50 of 0.04 µM. It exhibits significant antibacterial activity, particularly against Staphylococcus aureus, and can effectively attenuate the S. aureus-induced inflammatory response by inhibiting the activation of MAPK, NF-κB, and NLRP3-related proteins. This compound is relevant for research in antimicrobial resistance and inflammation pathways.
Grouped product items
Size Price Stock Qty
100mg
$20.00
In stock
5g
$205.00
In stock
10g
$370.00
In stock
25g
$770.00
In stock
Bulk Size
Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
Science VOLUME 369, ISSUE 6510 (2020)
Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionCloxacillin sodium is a β-lactam antibiotic and a potent β-lactamase inhibitor with an IC50 of 0.04 µM. It exhibits significant antibacterial activity, particularly against Staphylococcus aureus, and can effectively attenuate the S. aureus-induced inflammatory response by inhibiting the activation of MAPK, NF-κB, and NLRP3-related proteins. This compound is relevant for research in antimicrobial resistance and inflammation pathways.
Product Information
Catalog NumA46395
FormulaC19H17ClN3NaO5S
Molecular Weight457.86
CAS Number642-78-4
SMILESO=C(C(C(C(C=CC=C1)=C1Cl)=NO2)=C2C)N[C@H]3[C@](SC(C)4C)([H])N(C3=O)[C@H]4C(O[Na])=O
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