JNJ-18038683 free base

Catalog No.: A29626
5-HT Receptor Antagonist
JNJ-18038683 free base is a potent antagonist of the 5-Hydroxytryptamine Type 7 (5-HT7) receptor, demonstrating pKis of 8.19 and 8.20 for rat and human 5-HT7 receptors, respectively, in HEK293 cell assays. This compound exhibits significant biological activity relevant for the investigation of psychiatric disorders and neuropharmacology. It serves as a valuable tool for researchers exploring the therapeutic potential of 5-HT7 receptor modulation.
Grouped product items
Size Price Stock Qty
25mg
$1,275.00
In stock
50mg
$1,625.00
In stock
100mg
$2,000.00
In stock
Bulk Size
Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
Science VOLUME 369, ISSUE 6510 (2020)
Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionJNJ-18038683 free base is a potent antagonist of the 5-Hydroxytryptamine Type 7 (5-HT7) receptor, demonstrating pKis of 8.19 and 8.20 for rat and human 5-HT7 receptors, respectively, in HEK293 cell assays. This compound exhibits significant biological activity relevant for the investigation of psychiatric disorders and neuropharmacology. It serves as a valuable tool for researchers exploring the therapeutic potential of 5-HT7 receptor modulation.
Product Information
Catalog NumA29626
FormulaC20H20ClN3
Molecular Weight337.85
CAS Number851373-91-6
SMILESClC1=CC=C(C2=NN(CC3=CC=CC=C3)C4=C2CCNCC4)C=C1
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