MCT-IN-1

Catalog No.: A67483
MCT Inhibitor
MCT-IN-1 is a potent inhibitor of monocarboxylate transporters (MCT1 and MCT4), exhibiting IC50 values of 9 nM and 14 nM, respectively. This compound is particularly relevant for research into solid tumors, offering valuable insights into metabolic modulation and therapeutic strategies targeting tumor microenvironments. MCT-IN-1 serves as a crucial tool for investigating the role of lactate transport in cancer cell proliferation and survival.
Grouped product items
Size Price Stock Qty
5mg
$80.00
In stock
10mg
$125.00
In stock
25mg
$265.00
In stock
50mg
$410.00
In stock
100mg
$2,110.00
In stock
Bulk Size
Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
Science VOLUME 369, ISSUE 6510 (2020)
Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionMCT-IN-1 is a potent inhibitor of monocarboxylate transporters (MCT1 and MCT4), exhibiting IC50 values of 9 nM and 14 nM, respectively. This compound is particularly relevant for research into solid tumors, offering valuable insights into metabolic modulation and therapeutic strategies targeting tumor microenvironments. MCT-IN-1 serves as a crucial tool for investigating the role of lactate transport in cancer cell proliferation and survival.
Product Information
Catalog NumA67483
FormulaC19H26N2O3
Molecular Weight330.42
CAS Number1685273-57-7
SMILESCCCCN(C1=CC(OC)=C(C=C1)/C=C(C#N)/C(O)=O)CCCC
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