Apixaban 4,5-dehydro carboxylic acid ethyl ester

Catalog No.: A99996
Drug Impurity
Apixaban 4,5-dehydro carboxylic acid ethyl ester is a known drug impurity associated with the anticoagulant Apixaban. This impurity may influence the pharmacokinetic and pharmacodynamic profiles of the parent compound, making it relevant for bioanalytical studies and quality control during drug development. Researchers can utilize this compound to investigate the stability and degradation pathways of Apixaban, as well as to assess the potential impacts of impurities on therapeutic efficacy.
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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
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Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
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Nature volume 551, pages639-643 (2017)
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Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionApixaban 4,5-dehydro carboxylic acid ethyl ester is a known drug impurity associated with the anticoagulant Apixaban. This impurity may influence the pharmacokinetic and pharmacodynamic profiles of the parent compound, making it relevant for bioanalytical studies and quality control during drug development. Researchers can utilize this compound to investigate the stability and degradation pathways of Apixaban, as well as to assess the potential impacts of impurities on therapeutic efficacy.
Product Information
Catalog NumA99996
FormulaC27H26N4O5
Molecular Weight486.52
CAS Number2514951-00-7
SMILESO=C(C1=NN(C2=CC=C(OC)C=C2)C3=C1C=CN(C4=CC=C(N5C(CCCC5)=O)C=C4)C3=O)OCC
Useful Calculator

This calculator helps you calculate mass of compound based on solution concentration, volume and molecular weight in a specific solution using the formula:

Mass (mg) = Concentration (mM) × Volume (mL) × Molecular Weight (g/mol)

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Calculate the dilution required to prepare a stock solution.
This equation is commonly abbreviated as: C1V1 = C2V2

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