FD1024

Catalog No.: A40896
PIM Inhibitor
FD1024 is a potent PIM inhibitor with IC50 values of 1.96 nM, 38.9 nM, and 4.17 nM for PIM1, PIM2, and PIM3, respectively. This compound exhibits strong antiproliferative activity against various acute myeloid leukemia (AML) cell lines, showing effective concentrations of 0.16 μM, 0.12 μM, 1.05 μM, and 1.39 μM for EOL-1, MV-4-11, KG-1, and MOLM-16 cells. Additionally, FD1024 demonstrates significant antitumor efficacy in in vivo mouse models, making it a valuable tool for research into AML therapeutic strategies.
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Size Stock
5mg
10mg
50mg
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Bulk Discount
Free Delivery on orders over $500
Research use only. We do not sell to patients.

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Adooq Products cited in reputable paper
Science VOLUME 380, ISSUE 6663 (2023)
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Science VOLUME 356, ISSUE 6336 (2017)
Cell Vol. 185 Issue 23 p4428-4447.e28
Cell Vol 177, Issue 7, p1933-1947.e25
Cell Vol 156, Issue 5, p857-1114
Nature Volume 622 Issue 7982 (2023)
Nature volume 620, pages890-897 (2023)
Nature volume 610, pages540-546 (2022)
Nature volume 588, pages83-88 (2020)
Nature volume 574, pages268-272 (2019)
Nature volume 573, pages539-545 (2019)
Nature volume 567, pages118-122 (2019)
Nature volume 551, pages639-643 (2017)
Nature volume 551, pages247-250 (2017)
Nature volume 548, pages356-360 (2017)
Nature volume 545, pages187-192 (2017)
Biological Activity
DescriptionFD1024 is a potent PIM inhibitor with IC50 values of 1.96 nM, 38.9 nM, and 4.17 nM for PIM1, PIM2, and PIM3, respectively. This compound exhibits strong antiproliferative activity against various acute myeloid leukemia (AML) cell lines, showing effective concentrations of 0.16 μM, 0.12 μM, 1.05 μM, and 1.39 μM for EOL-1, MV-4-11, KG-1, and MOLM-16 cells. Additionally, FD1024 demonstrates significant antitumor efficacy in in vivo mouse models, making it a valuable tool for research into AML therapeutic strategies.
Product Information
Catalog NumA40896
FormulaC21H20F2N4O2S
Molecular Weight430.47
CAS Number1422456-47-0
SMILESO=C(C1=CSC(C2=C(F)C=CC=C2F)=N1)NC3=C(O[C@H]4CC[C@H](N)CC4)C=CN=C3
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